好好学习,天天向上

CCNA 640-802-Hotspot(Topology)

上一篇 / 下一篇  2008-06-11 15:22:42

  • Hotspot:
    最新的CCNA640-802题库hotspot题详解:
  • Question 1:
    If router has a packet destination address 192.168.1.255. What describes the operation of the network?
    Answer:
    R1 will drop this packet because it is not a valid ip address
    Explanation:
    The destination IP address192.168.1.255is broadcast address of thenetwork192.168.1.0 /24 on router R1.
    Network Address: 192.168.1.0 subnet mask: 255.255.255.0
    Network valid host range: 192.168.1.1 – 192.168.1.254
    Broadcast Address: 192.168.1.255
    Since router (R1) received a packet with destination IP address (192.168.1.255) which is broadcast address so it simply discards the packet as Forwarding broadcast packet can lead to severe storms of packets, and if uncontrolled could lead to network overload.
  • Question 2:
    Users on the 192.168.1.0 /24 network must access files located on the server 1. Whatroutecould be configured on router R1 for the file requests to reach the server ?
    Answer:
    ip route 0.0.0.0 0.0.0.0 s 0/0/0
    Explanation:
    To enable users on 192.168.1.0 network to access files on server1, we need to establish a default static route.
    Static route syntax:
    ip route prefix mask {ip-address interface-type interface-number [ip-address]} [distance] [name] [permanent track number] [tag tag]
    From the options provided for this question the correct default static route is
    ip route0.0.0.00.0.0.0 S 0/0/0
    PS:As per best practices static route to server1 on R1 should have been
    ip route 209.165.200.0 255.255.255.0 209.165.100.200
    (or)
    ip route 209.165.200.0 255.255.255.0 s 0/0/0
  • Question 3:
    When a packet is sent from Host1 to Server1,in how many different frames will the packet be encapsulated as it is sent across the internetwork?
    Answer:
    3
    Explanation:
    First:Host1 encapsulates the packet into frames and forwards to theswitch.
    Switch in turn forwards the same frame. to router R1.
    Second:Router R1 receives the frame. on one interface and it is encapsulates into new packet once it leaves the router R1 towards the direction of server1.
    Third:R2 receives this packet and it also encapsulates the frame. into new packet when it is forwarded to server1 on different interface of R2.
    Therefore the packet is sent using three different frames to reach from Host1 to server1.
  • Question 4:
    What must be configured on the network in order for users on the internet to view web pages located on web server2?
    Answer:
    On router R1, configure aNATto translate address on 209.165.100.0 to 192.168.1.0 network.
  • Question 5:
    The router address 192.168.1.250 is the default gateway for both web server2 and host 1. What is the correct subnet mask for this network?
    Answer:
    255.255.255.0
    Explanation:
    Given subnet mask for this network is 255.255.255.0 based on the exhibit.
    To find the correct subnet mask for this network based on number of devices shown in the exhibit that are already configured with IP address and by not wasting IP addresses scheme.
    The network 192.168.1.0 consists of only three devices as per the exhibits which are configured with IP address.
    R1(fa 0/0): 192.168.1.250 ( default gateway as per the question)
    Host1: 192.168.1.106
    Web server 2: 192.168.1.10
    correct subnet mask that will cover all above IP address is 255.255.255.0

TAG:

 

评分:0

我来说两句

显示全部

:loveliness: :handshake :victory: :funk: :time: :kiss: :call: :hug: :lol :'( :Q :L ;P :$ :P :o :@ :D :( :)

日历

« 2008-08-28  
     12
3456789
10111213141516
17181920212223
24252627282930
31      

数据统计

  • 访问量: 15950
  • 日志数: 200
  • 图片数: 2
  • 建立时间: 2007-10-16
  • 更新时间: 2008-08-24

RSS订阅

Open Toolbar